Base | Representation |
---|---|
bin | 1100010010000000001000… |
… | …1010010010110000111011 |
3 | 1202210220200002200112001112 |
4 | 3010200002022102300323 |
5 | 3232214442314300410 |
6 | 44415214341310535 |
7 | 2562406113226001 |
oct | 304400212226073 |
9 | 52726602615045 |
10 | 13503413431355 |
11 | 4336846937741 |
12 | 1621075a0544b |
13 | 76c49c052653 |
14 | 3497d6710a71 |
15 | 1863c4cc7105 |
hex | c4802292c3b |
13503413431355 has 4 divisors (see below), whose sum is σ = 16204096117632. Its totient is φ = 10802730745080.
The previous prime is 13503413431307. The next prime is 13503413431373. The reversal of 13503413431355 is 55313431430531.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13503413431355 - 28 = 13503413431099 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1350341343131 + ... + 1350341343140.
It is an arithmetic number, because the mean of its divisors is an integer number (4051024029408).
Almost surely, 213503413431355 is an apocalyptic number.
13503413431355 is a deficient number, since it is larger than the sum of its proper divisors (2700682686277).
13503413431355 is an equidigital number, since it uses as much as digits as its factorization.
13503413431355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2700682686276.
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 13503413431355 its reverse (55313431430531), we get a palindrome (68816844861886).
The spelling of 13503413431355 in words is "thirteen trillion, five hundred three billion, four hundred thirteen million, four hundred thirty-one thousand, three hundred fifty-five".
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