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1350344053403 = 10113369743103
BaseRepresentation
bin10011101001100110110…
…001110001001010011011
311210002110210120100101122
4103221212301301022123
5134111001034202103
62512201155235455
7166362533033312
oct23514661611233
94702423510348
101350344053403
114807500186a4
121998575a8b8b
139a44c21a757
14494dd879279
15251d3acbb38
hex13a66c7129b

1350344053403 has 4 divisors (see below), whose sum is σ = 1363713796608. Its totient is φ = 1336974310200.

The previous prime is 1350344053393. The next prime is 1350344053433. The reversal of 1350344053403 is 3043504430531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1350344053403 - 28 = 1350344053147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1350344053433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6684871451 + ... + 6684871652.

It is an arithmetic number, because the mean of its divisors is an integer number (340928449152).

Almost surely, 21350344053403 is an apocalyptic number.

1350344053403 is a deficient number, since it is larger than the sum of its proper divisors (13369743205).

1350344053403 is a wasteful number, since it uses less digits than its factorization.

1350344053403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13369743204.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 1350344053403 its reverse (3043504430531), we get a palindrome (4393848483934).

The spelling of 1350344053403 in words is "one trillion, three hundred fifty billion, three hundred forty-four million, fifty-three thousand, four hundred three".

Divisors: 1 101 13369743103 1350344053403