Base | Representation |
---|---|
bin | 10011101001101001001… |
… | …010100010100000100011 |
3 | 11210002120120220222221012 |
4 | 103221221022202200203 |
5 | 134111041312221121 |
6 | 2512205145451135 |
7 | 166363530321332 |
oct | 23515112424043 |
9 | 4702516828835 |
10 | 1350384101411 |
11 | 480770691324 |
12 | 199868aa0aab |
13 | 9a4576000b7 |
14 | 49504d01d19 |
15 | 251d738cc5b |
hex | 13a692a2823 |
1350384101411 has 8 divisors (see below), whose sum is σ = 1351740546144. Its totient is φ = 1349028207360.
The previous prime is 1350384101387. The next prime is 1350384101449. The reversal of 1350384101411 is 1141014830531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1350384101411 - 214 = 1350384085027 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1350384101461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4859906 + ... + 5130248.
It is an arithmetic number, because the mean of its divisors is an integer number (168967568268).
Almost surely, 21350384101411 is an apocalyptic number.
1350384101411 is a deficient number, since it is larger than the sum of its proper divisors (1356444733).
1350384101411 is a wasteful number, since it uses less digits than its factorization.
1350384101411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 275341.
The product of its (nonzero) digits is 5760, while the sum is 32.
Adding to 1350384101411 its reverse (1141014830531), we get a palindrome (2491398931942).
The spelling of 1350384101411 in words is "one trillion, three hundred fifty billion, three hundred eighty-four million, one hundred one thousand, four hundred eleven".
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