13504040137613 has 2 divisors, whose sum is σ = 13504040137614. Its totient is φ = 13504040137612.

The previous prime is 13504040137573. The next prime is 13504040137619. The reversal of 13504040137613 is 31673104040531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11108175749449 + 2395864388164 = 3332893^2 + 1547858^2 .

It is an emirp because it is prime and its reverse (31673104040531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13504040137613 - 2¹⁶ = 13504040072077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13504040137619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6752020068806 + 6752020068807.

It is an arithmetic number, because the mean of its divisors is an integer number (6752020068807).

Almost surely, 2^{13504040137613} is an apocalyptic number.

It is an amenable number.

13504040137613 is a deficient number, since it is larger than the sum of its proper divisors (1).

13504040137613 is an equidigital number, since it uses as much as digits as its factorization.

13504040137613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 38.

The spelling of 13504040137613 in words is "thirteen trillion, five hundred four billion, forty million, one hundred thirty-seven thousand, six hundred thirteen".