135042311333 has 4 divisors (see below), whose sum is σ = 135043072320. Its totient is φ = 135041550348.

The previous prime is 135042311309. The next prime is 135042311357. The reversal of 135042311333 is 333113240531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 333113240531 = 809 ⋅411759259.

It is an interprime number because it is at equal distance from previous prime (135042311309) and next prime (135042311357).

It is a cyclic number.

It is not a de Polignac number, because 135042311333 - 2¹⁴ = 135042294949 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135042311296 and 135042311305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135042301333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42266 + ... + 521412.

It is an arithmetic number, because the mean of its divisors is an integer number (33760768080).

Almost surely, 2^135042311333 is an apocalyptic number.

It is an amenable number.

135042311333 is a deficient number, since it is larger than the sum of its proper divisors (760987).

135042311333 is an equidigital number, since it uses as much as digits as its factorization.

135042311333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 760986.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 135042311333 its reverse (333113240531), we get a palindrome (468155551864).

The spelling of 135042311333 in words is "one hundred thirty-five billion, forty-two million, three hundred eleven thousand, three hundred thirty-three".