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1350426441557 is a prime number
BaseRepresentation
bin10011101001101011101…
…100000011011101010101
311210002200112121002200202
4103221223230003131111
5134111133132112212
62512213301150245
7166364553234104
oct23515354033525
94702615532622
101350426441557
11480792580086
1219987b0bb385
139a463305b3b
144950a7a403b
15251dae530c2
hex13a6bb03755

1350426441557 has 2 divisors, whose sum is σ = 1350426441558. Its totient is φ = 1350426441556.

The previous prime is 1350426441499. The next prime is 1350426441589. The reversal of 1350426441557 is 7551446240531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1115556327601 + 234870113956 = 1056199^2 + 484634^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350426441557 - 236 = 1281706964821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350426441157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675213220778 + 675213220779.

It is an arithmetic number, because the mean of its divisors is an integer number (675213220779).

Almost surely, 21350426441557 is an apocalyptic number.

It is an amenable number.

1350426441557 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350426441557 is an equidigital number, since it uses as much as digits as its factorization.

1350426441557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016000, while the sum is 47.

The spelling of 1350426441557 in words is "one trillion, three hundred fifty billion, four hundred twenty-six million, four hundred forty-one thousand, five hundred fifty-seven".