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135043346541 = 3214192101613
BaseRepresentation
bin111110111000100110…
…1011111000001101101
3110220120101212210110110
41331301031133001231
54203032044042131
6142012115330233
712520333335405
oct1756115370155
9426511783413
10135043346541
11522a94a3024
12222098b0979
13c9719cc25c
146771211805
1537a59cd646
hex1f7135f06d

135043346541 has 8 divisors (see below), whose sum is σ = 180066287520. Its totient is φ = 90024651632.

The previous prime is 135043346531. The next prime is 135043346569. The reversal of 135043346541 is 145643340531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135043346541 - 213 = 135043338349 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 135043346541.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135043346531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 986550 + ... + 1115063.

It is an arithmetic number, because the mean of its divisors is an integer number (22508285940).

Almost surely, 2135043346541 is an apocalyptic number.

It is an amenable number.

135043346541 is a deficient number, since it is larger than the sum of its proper divisors (45022940979).

135043346541 is a wasteful number, since it uses less digits than its factorization.

135043346541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2123035.

The product of its (nonzero) digits is 259200, while the sum is 39.

The spelling of 135043346541 in words is "one hundred thirty-five billion, forty-three million, three hundred forty-six thousand, five hundred forty-one".

Divisors: 1 3 21419 64257 2101613 6304839 45014448847 135043346541