1350434399981 has 2 divisors, whose sum is σ = 1350434399982. Its totient is φ = 1350434399980.

The previous prime is 1350434399947. The next prime is 1350434400037. The reversal of 1350434399981 is 1899934340531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1322247012100 + 28187387881 = 1149890^2 + 167891^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350434399981 - 2³⁰ = 1349360658157 is a prime.

It is a super-2 number, since 2×1350434399981² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1350434399981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350434398981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675217199990 + 675217199991.

It is an arithmetic number, because the mean of its divisors is an integer number (675217199991).

Almost surely, 2^{1350434399981} is an apocalyptic number.

It is an amenable number.

1350434399981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350434399981 is an equidigital number, since it uses as much as digits as its factorization.

1350434399981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12597120, while the sum is 59.

The spelling of 1350434399981 in words is "one trillion, three hundred fifty billion, four hundred thirty-four million, three hundred ninety-nine thousand, nine hundred eighty-one".