Base | Representation |
---|---|
bin | 11110101101001001000101… |
… | …101001001000001001100111 |
3 | 122201011000221210202010200220 |
4 | 132231021011221020021213 |
5 | 120200023122203130043 |
6 | 1155114050304135423 |
7 | 40305400365363654 |
oct | 3655110551101147 |
9 | 581130853663626 |
10 | 135043530130023 |
11 | 3a0357041a9759 |
12 | 13190411007573 |
13 | 5a4771cb87528 |
14 | 254c1dacb4c2b |
15 | 1092bd3661483 |
hex | 7ad245a48267 |
135043530130023 has 4 divisors (see below), whose sum is σ = 180058040173368. Its totient is φ = 90029020086680.
The previous prime is 135043530130009. The next prime is 135043530130031. The reversal of 135043530130023 is 320031035340531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135043530130023 - 210 = 135043530128999 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135043530130073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22507255021668 + ... + 22507255021673.
It is an arithmetic number, because the mean of its divisors is an integer number (45014510043342).
Almost surely, 2135043530130023 is an apocalyptic number.
135043530130023 is a deficient number, since it is larger than the sum of its proper divisors (45014510043345).
135043530130023 is an equidigital number, since it uses as much as digits as its factorization.
135043530130023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45014510043344.
The product of its (nonzero) digits is 48600, while the sum is 33.
Adding to 135043530130023 its reverse (320031035340531), we get a palindrome (455074565470554).
The spelling of 135043530130023 in words is "one hundred thirty-five trillion, forty-three billion, five hundred thirty million, one hundred thirty thousand, twenty-three".
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