Base | Representation |
---|---|
bin | 111110111000101000… |
… | …0001110110010100111 |
3 | 110220120110020101000112 |
4 | 1331301100032302213 |
5 | 4203032240111341 |
6 | 142012143003235 |
7 | 12520342424336 |
oct | 1756120166247 |
9 | 426513211015 |
10 | 135044066471 |
11 | 522a9944a06 |
12 | 22209b9951b |
13 | c971bc1b52 |
14 | 677135bd1d |
15 | 37a5ac1aeb |
hex | 1f7140eca7 |
135044066471 has 2 divisors, whose sum is σ = 135044066472. Its totient is φ = 135044066470.
The previous prime is 135044066461. The next prime is 135044066567. The reversal of 135044066471 is 174660440531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135044066471 - 26 = 135044066407 is a prime.
It is a super-3 number, since 3×1350440664713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135044066411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67522033235 + 67522033236.
It is an arithmetic number, because the mean of its divisors is an integer number (67522033236).
Almost surely, 2135044066471 is an apocalyptic number.
135044066471 is a deficient number, since it is larger than the sum of its proper divisors (1).
135044066471 is an equidigital number, since it uses as much as digits as its factorization.
135044066471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
The spelling of 135044066471 in words is "one hundred thirty-five billion, forty-four million, sixty-six thousand, four hundred seventy-one".
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