1350454121113 has 4 divisors (see below), whose sum is σ = 1383392026548. Its totient is φ = 1317516215680.

The previous prime is 1350454121083. The next prime is 1350454121117. The reversal of 1350454121113 is 3111214540531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 421086783744 + 929367337369 = 648912^2 + 964037^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350454121113 - 2²¹ = 1350452023961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1350454121117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16468952656 + ... + 16468952737.

It is an arithmetic number, because the mean of its divisors is an integer number (345848006637).

Almost surely, 2^{1350454121113} is an apocalyptic number.

It is an amenable number.

1350454121113 is a deficient number, since it is larger than the sum of its proper divisors (32937905435).

1350454121113 is an equidigital number, since it uses as much as digits as its factorization.

1350454121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32937905434.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 1350454121113 its reverse (3111214540531), we get a palindrome (4461668661644).

The spelling of 1350454121113 in words is "one trillion, three hundred fifty billion, four hundred fifty-four million, one hundred twenty-one thousand, one hundred thirteen".