Search a number
-
+
135054305041 is a prime number
BaseRepresentation
bin111110111000111011…
…1010010011100010001
3110220121011111112200211
41331301313102130101
54203042400230131
6142013150244121
712520525436365
oct1756167223421
9426534445624
10135054305041
11523046a8337
12222114b6641
13c974068186
1467728652a5
1537a69455b1
hex1f71dd2711

135054305041 has 2 divisors, whose sum is σ = 135054305042. Its totient is φ = 135054305040.

The previous prime is 135054305017. The next prime is 135054305047. The reversal of 135054305041 is 140503450531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134612674816 + 441630225 = 366896^2 + 21015^2 .

It is a cyclic number.

It is not a de Polignac number, because 135054305041 - 211 = 135054302993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135054304994 and 135054305012.

It is not a weakly prime, because it can be changed into another prime (135054305047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67527152520 + 67527152521.

It is an arithmetic number, because the mean of its divisors is an integer number (67527152521).

Almost surely, 2135054305041 is an apocalyptic number.

It is an amenable number.

135054305041 is a deficient number, since it is larger than the sum of its proper divisors (1).

135054305041 is an equidigital number, since it uses as much as digits as its factorization.

135054305041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 135054305041 its reverse (140503450531), we get a palindrome (275557755572).

The spelling of 135054305041 in words is "one hundred thirty-five billion, fifty-four million, three hundred five thousand, forty-one".