Base | Representation |
---|---|
bin | 111110111000111011… |
… | …1010010011100010001 |
3 | 110220121011111112200211 |
4 | 1331301313102130101 |
5 | 4203042400230131 |
6 | 142013150244121 |
7 | 12520525436365 |
oct | 1756167223421 |
9 | 426534445624 |
10 | 135054305041 |
11 | 523046a8337 |
12 | 222114b6641 |
13 | c974068186 |
14 | 67728652a5 |
15 | 37a69455b1 |
hex | 1f71dd2711 |
135054305041 has 2 divisors, whose sum is σ = 135054305042. Its totient is φ = 135054305040.
The previous prime is 135054305017. The next prime is 135054305047. The reversal of 135054305041 is 140503450531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134612674816 + 441630225 = 366896^2 + 21015^2 .
It is a cyclic number.
It is not a de Polignac number, because 135054305041 - 211 = 135054302993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135054304994 and 135054305012.
It is not a weakly prime, because it can be changed into another prime (135054305047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67527152520 + 67527152521.
It is an arithmetic number, because the mean of its divisors is an integer number (67527152521).
Almost surely, 2135054305041 is an apocalyptic number.
It is an amenable number.
135054305041 is a deficient number, since it is larger than the sum of its proper divisors (1).
135054305041 is an equidigital number, since it uses as much as digits as its factorization.
135054305041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 135054305041 its reverse (140503450531), we get a palindrome (275557755572).
The spelling of 135054305041 in words is "one hundred thirty-five billion, fifty-four million, three hundred five thousand, forty-one".
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