Base | Representation |
---|---|
bin | 111110111000111011… |
… | …1010010011100010111 |
3 | 110220121011111112201001 |
4 | 1331301313102130113 |
5 | 4203042400230142 |
6 | 142013150244131 |
7 | 12520525436404 |
oct | 1756167223427 |
9 | 426534445631 |
10 | 135054305047 |
11 | 523046a8342 |
12 | 222114b6647 |
13 | c97406818c |
14 | 67728652ab |
15 | 37a69455b7 |
hex | 1f71dd2717 |
135054305047 has 2 divisors, whose sum is σ = 135054305048. Its totient is φ = 135054305046.
The previous prime is 135054305041. The next prime is 135054305059. The reversal of 135054305047 is 740503450531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135054305047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135054304997 and 135054305015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135054305041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67527152523 + 67527152524.
It is an arithmetic number, because the mean of its divisors is an integer number (67527152524).
Almost surely, 2135054305047 is an apocalyptic number.
135054305047 is a deficient number, since it is larger than the sum of its proper divisors (1).
135054305047 is an equidigital number, since it uses as much as digits as its factorization.
135054305047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126000, while the sum is 37.
Adding to 135054305047 its reverse (740503450531), we get a palindrome (875557755578).
The spelling of 135054305047 in words is "one hundred thirty-five billion, fifty-four million, three hundred five thousand, forty-seven".
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