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1350553334113 = 19153137464171
BaseRepresentation
bin10011101001110011010…
…000000111000101100001
311210010000101100220120001
4103221303100013011201
5134111413123142423
62512234033020001
7166400653633204
oct23516320070541
94703011326501
101350553334113
1148084816a365
121998b56b4601
139a4836a40a9
144951d59593b
15251e716acad
hex13a73407161

1350553334113 has 8 divisors (see below), whose sum is σ = 1421647434720. Its totient is φ = 1279460468160.

The previous prime is 1350553334033. The next prime is 1350553334171. The reversal of 1350553334113 is 3114333550531.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-1350553334113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1350553334513) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2677518 + ... + 3141688.

It is an arithmetic number, because the mean of its divisors is an integer number (177705929340).

Almost surely, 21350553334113 is an apocalyptic number.

It is an amenable number.

1350553334113 is a deficient number, since it is larger than the sum of its proper divisors (71094100607).

1350553334113 is a wasteful number, since it uses less digits than its factorization.

1350553334113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 617327.

The product of its (nonzero) digits is 121500, while the sum is 37.

Adding to 1350553334113 its reverse (3114333550531), we get a palindrome (4464886884644).

The spelling of 1350553334113 in words is "one trillion, three hundred fifty billion, five hundred fifty-three million, three hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 19 153137 464171 2909603 8819249 71081754427 1350553334113