135062300131 has 4 divisors (see below), whose sum is σ = 147340691064. Its totient is φ = 122783909200.

The previous prime is 135062300099. The next prime is 135062300141. The reversal of 135062300131 is 131003260531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135062300131 - 2⁵ = 135062300099 is a prime.

It is a super-2 number, since 2×135062300131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135062300096 and 135062300105.

It is not an unprimeable number, because it can be changed into a prime (135062300141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6139195450 + ... + 6139195471.

It is an arithmetic number, because the mean of its divisors is an integer number (36835172766).

Almost surely, 2^135062300131 is an apocalyptic number.

135062300131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

135062300131 is a deficient number, since it is larger than the sum of its proper divisors (12278390933).

135062300131 is a wasteful number, since it uses less digits than its factorization.

135062300131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12278390932.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 135062300131 its reverse (131003260531), we get a palindrome (266065560662).

The spelling of 135062300131 in words is "one hundred thirty-five billion, sixty-two million, three hundred thousand, one hundred thirty-one".