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1351041755543 = 6668892025887
BaseRepresentation
bin10011101010010000010…
…111010010100110010111
311210011021102102021210122
4103222100113102212113
5134113413142134133
62512354321342155
7166416034304324
oct23522027224627
94704242367718
101351041755543
11480a78938637
12199a1119795b
139a530933c5c
14495683b5b4b
1525224e98498
hex13a905d2997

1351041755543 has 4 divisors (see below), whose sum is σ = 1351044448320. Its totient is φ = 1351039062768.

The previous prime is 1351041755513. The next prime is 1351041755593. The reversal of 1351041755543 is 3455571401531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1351041755543 - 222 = 1351037561239 is a prime.

It is a super-2 number, since 2×13510417555432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1351041755494 and 1351041755503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1351041755513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 346055 + ... + 1679832.

It is an arithmetic number, because the mean of its divisors is an integer number (337761112080).

Almost surely, 21351041755543 is an apocalyptic number.

1351041755543 is a deficient number, since it is larger than the sum of its proper divisors (2692777).

1351041755543 is an equidigital number, since it uses as much as digits as its factorization.

1351041755543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2692776.

The product of its (nonzero) digits is 630000, while the sum is 44.

The spelling of 1351041755543 in words is "one trillion, three hundred fifty-one billion, forty-one million, seven hundred fifty-five thousand, five hundred forty-three".

Divisors: 1 666889 2025887 1351041755543