Base | Representation |
---|---|
bin | 10011101010010000011… |
… | …001001001010001101111 |
3 | 11210011021110022222121111 |
4 | 103222100121021101233 |
5 | 134113413303213042 |
6 | 2512354340012451 |
7 | 166416041400460 |
oct | 23522031112157 |
9 | 4704243288544 |
10 | 1351042241647 |
11 | 480a7913a87a |
12 | 199a11391127 |
13 | 9a530a742a7 |
14 | 495684a0d67 |
15 | 25225042517 |
hex | 13a9064946f |
1351042241647 has 4 divisors (see below), whose sum is σ = 1544048276176. Its totient is φ = 1158036207120.
The previous prime is 1351042241641. The next prime is 1351042241651. The reversal of 1351042241647 is 7461422401531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1351042241647 - 239 = 801286427759 is a prime.
It is a super-3 number, since 3×13510422416473 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1351042241641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96503017254 + ... + 96503017267.
It is an arithmetic number, because the mean of its divisors is an integer number (386012069044).
Almost surely, 21351042241647 is an apocalyptic number.
1351042241647 is a deficient number, since it is larger than the sum of its proper divisors (193006034529).
1351042241647 is an equidigital number, since it uses as much as digits as its factorization.
1351042241647 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 193006034528.
The product of its (nonzero) digits is 161280, while the sum is 40.
The spelling of 1351042241647 in words is "one trillion, three hundred fifty-one billion, forty-two million, two hundred forty-one thousand, six hundred forty-seven".
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