Base | Representation |
---|---|
bin | 10011101010010001101… |
… | …001001011101101100001 |
3 | 11210011022220210221210201 |
4 | 103222101221023231201 |
5 | 134113434141120022 |
6 | 2512400405425201 |
7 | 166416414625135 |
oct | 23522151135541 |
9 | 4704286727721 |
10 | 1351063223137 |
11 | 480a89a70551 |
12 | 199a1840b201 |
13 | 9a53520c384 |
14 | 4956b1a33c5 |
15 | 25226cd9127 |
hex | 13a91a4bb61 |
1351063223137 has 2 divisors, whose sum is σ = 1351063223138. Its totient is φ = 1351063223136.
The previous prime is 1351063223119. The next prime is 1351063223143. The reversal of 1351063223137 is 7313223601531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1320938761041 + 30124462096 = 1149321^2 + 173564^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351063223137 - 231 = 1348915739489 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1351063223096 and 1351063223105.
It is not a weakly prime, because it can be changed into another prime (1351063203137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675531611568 + 675531611569.
It is an arithmetic number, because the mean of its divisors is an integer number (675531611569).
Almost surely, 21351063223137 is an apocalyptic number.
It is an amenable number.
1351063223137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351063223137 is an equidigital number, since it uses as much as digits as its factorization.
1351063223137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 37.
Adding to 1351063223137 its reverse (7313223601531), we get a palindrome (8664286824668).
The spelling of 1351063223137 in words is "one trillion, three hundred fifty-one billion, sixty-three million, two hundred twenty-three thousand, one hundred thirty-seven".
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