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1351063223143 is a prime number
BaseRepresentation
bin10011101010010001101…
…001001011101101100111
311210011022220210221210221
4103222101221023231213
5134113434141120033
62512400405425211
7166416414625144
oct23522151135547
94704286727727
101351063223143
11480a89a70557
12199a1840b207
139a53520c38a
144956b1a33cb
1525226cd912d
hex13a91a4bb67

1351063223143 has 2 divisors, whose sum is σ = 1351063223144. Its totient is φ = 1351063223142.

The previous prime is 1351063223137. The next prime is 1351063223161. The reversal of 1351063223143 is 3413223601531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1351063223143 - 221 = 1351061125991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1351063223099 and 1351063223108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351063223183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675531611571 + 675531611572.

It is an arithmetic number, because the mean of its divisors is an integer number (675531611572).

Almost surely, 21351063223143 is an apocalyptic number.

1351063223143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351063223143 is an equidigital number, since it uses as much as digits as its factorization.

1351063223143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 34.

Adding to 1351063223143 its reverse (3413223601531), we get a palindrome (4764286824674).

The spelling of 1351063223143 in words is "one trillion, three hundred fifty-one billion, sixty-three million, two hundred twenty-three thousand, one hundred forty-three".