1351114726439 has 2 divisors, whose sum is σ = 1351114726440. Its totient is φ = 1351114726438.

The previous prime is 1351114726373. The next prime is 1351114726469. The reversal of 1351114726439 is 9346274111531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1351114726439 - 2⁸ = 1351114726183 is a prime.

It is a super-3 number, since 3×1351114726439³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1351114726393 and 1351114726402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351114726469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675557363219 + 675557363220.

It is an arithmetic number, because the mean of its divisors is an integer number (675557363220).

Almost surely, 2^{1351114726439} is an apocalyptic number.

1351114726439 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351114726439 is an equidigital number, since it uses as much as digits as its factorization.

1351114726439 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 544320, while the sum is 47.

The spelling of 1351114726439 in words is "one trillion, three hundred fifty-one billion, one hundred fourteen million, seven hundred twenty-six thousand, four hundred thirty-nine".