Base | Representation |
---|---|
bin | 10011101010010101010… |
… | …010010101011001001011 |
3 | 11210011111011211010121011 |
4 | 103222111102111121023 |
5 | 134114100312423342 |
6 | 2512410431424351 |
7 | 166421056263223 |
oct | 23522522253113 |
9 | 4704434733534 |
10 | 1351124342347 |
11 | 48101051629a |
12 | 199a349850b7 |
13 | 9a544a8b8a0 |
14 | 49575353083 |
15 | 2522c35d717 |
hex | 13a9549564b |
1351124342347 has 16 divisors (see below), whose sum is σ = 1543029953472. Its totient is φ = 1172013096960.
The previous prime is 1351124342263. The next prime is 1351124342401. The reversal of 1351124342347 is 7432434211531.
It is not a de Polignac number, because 1351124342347 - 231 = 1348976858699 is a prime.
It is a super-2 number, since 2×13511243423472 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1351124340347) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4581654 + ... + 4867627.
It is an arithmetic number, because the mean of its divisors is an integer number (96439372092).
Almost surely, 21351124342347 is an apocalyptic number.
1351124342347 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
1351124342347 is a deficient number, since it is larger than the sum of its proper divisors (191905611125).
1351124342347 is a wasteful number, since it uses less digits than its factorization.
1351124342347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9449958.
The product of its digits is 241920, while the sum is 40.
Adding to 1351124342347 its reverse (7432434211531), we get a palindrome (8783558553878).
The spelling of 1351124342347 in words is "one trillion, three hundred fifty-one billion, one hundred twenty-four million, three hundred forty-two thousand, three hundred forty-seven".
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