Base | Representation |
---|---|
bin | 1100010010011101111110… |
… | …0101100001010110001100 |
3 | 1202211200100022200001120101 |
4 | 3010213133211201112030 |
5 | 3232332343331113004 |
6 | 44423021232500444 |
7 | 2563111444053436 |
oct | 304473745412614 |
9 | 52750308601511 |
10 | 13511423301004 |
11 | 433a187236322 |
12 | 16227303aa724 |
13 | 77017763cba5 |
14 | 349d56427656 |
15 | 1866e30c1ba4 |
hex | c49df96158c |
13511423301004 has 24 divisors (see below), whose sum is σ = 23958405646560. Its totient is φ = 6666686686464.
The previous prime is 13511423301001. The next prime is 13511423301007. The reversal of 13511423301004 is 40010332411531.
13511423301004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13511423301001) and next prime (13511423301007).
It is not an unprimeable number, because it can be changed into a prime (13511423301001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65164024 + ... + 65371039.
It is an arithmetic number, because the mean of its divisors is an integer number (998266901940).
Almost surely, 213511423301004 is an apocalyptic number.
It is an amenable number.
13511423301004 is a deficient number, since it is larger than the sum of its proper divisors (10446982345556).
13511423301004 is a wasteful number, since it uses less digits than its factorization.
13511423301004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130535409 (or 130535407 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13511423301004 its reverse (40010332411531), we get a palindrome (53521755712535).
The spelling of 13511423301004 in words is "thirteen trillion, five hundred eleven billion, four hundred twenty-three million, three hundred one thousand, four".
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