Base | Representation |
---|---|
bin | 111110111010101110… |
… | …0010001010100010011 |
3 | 110220202100110012101201 |
4 | 1331311130101110103 |
5 | 4203203232101121 |
6 | 142023133012031 |
7 | 12522154603363 |
oct | 1756534212423 |
9 | 426670405351 |
10 | 135114331411 |
11 | 52335577004 |
12 | 22229624017 |
13 | c983624137 |
14 | 677a80c9a3 |
15 | 37abd50e91 |
hex | 1f75711513 |
135114331411 has 2 divisors, whose sum is σ = 135114331412. Its totient is φ = 135114331410.
The previous prime is 135114331403. The next prime is 135114331421. The reversal of 135114331411 is 114133411531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135114331411 - 23 = 135114331403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 135114331411.
It is not a weakly prime, because it can be changed into another prime (135114331421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67557165705 + 67557165706.
It is an arithmetic number, because the mean of its divisors is an integer number (67557165706).
Almost surely, 2135114331411 is an apocalyptic number.
135114331411 is a deficient number, since it is larger than the sum of its proper divisors (1).
135114331411 is an equidigital number, since it uses as much as digits as its factorization.
135114331411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2160, while the sum is 28.
Adding to 135114331411 its reverse (114133411531), we get a palindrome (249247742942).
The spelling of 135114331411 in words is "one hundred thirty-five billion, one hundred fourteen million, three hundred thirty-one thousand, four hundred eleven".
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