Base | Representation |
---|---|
bin | 10011101010010110111… |
… | …000000100100101000001 |
3 | 11210011120001000002201001 |
4 | 103222112320010211001 |
5 | 134114124124342121 |
6 | 2512413223212001 |
7 | 166421532051616 |
oct | 23522670044501 |
9 | 4704501002631 |
10 | 1351151012161 |
11 | 481024581765 |
12 | 199a418a7001 |
13 | 9a54a468b42 |
14 | 49578ad650d |
15 | 2522e87a991 |
hex | 13a96e04941 |
1351151012161 has 2 divisors, whose sum is σ = 1351151012162. Its totient is φ = 1351151012160.
The previous prime is 1351151012147. The next prime is 1351151012231. The reversal of 1351151012161 is 1612101511531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 913469531536 + 437681480625 = 955756^2 + 661575^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351151012161 - 27 = 1351151012033 is a prime.
It is not a weakly prime, because it can be changed into another prime (1351151022161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675575506080 + 675575506081.
It is an arithmetic number, because the mean of its divisors is an integer number (675575506081).
Almost surely, 21351151012161 is an apocalyptic number.
It is an amenable number.
1351151012161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351151012161 is an equidigital number, since it uses as much as digits as its factorization.
1351151012161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 900, while the sum is 28.
Adding to 1351151012161 its reverse (1612101511531), we get a palindrome (2963252523692).
The spelling of 1351151012161 in words is "one trillion, three hundred fifty-one billion, one hundred fifty-one million, twelve thousand, one hundred sixty-one".
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