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13511969953 is a prime number
BaseRepresentation
bin11001001010110000…
…00100110010100001
31021212200011012012121
430211120010302201
5210133031014303
610112440224241
7655560564256
oct144530046241
937780135177
1013511969953
115804178019
12275116b081
1313744881c1
1492275942d
155413819bd
hex325604ca1

13511969953 has 2 divisors, whose sum is σ = 13511969954. Its totient is φ = 13511969952.

The previous prime is 13511969941. The next prime is 13511969957. The reversal of 13511969953 is 35996911531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12497674849 + 1014295104 = 111793^2 + 31848^2 .

It is a cyclic number.

It is not a de Polignac number, because 13511969953 - 29 = 13511969441 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13511969953.

It is not a weakly prime, because it can be changed into another prime (13511969957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6755984976 + 6755984977.

It is an arithmetic number, because the mean of its divisors is an integer number (6755984977).

Almost surely, 213511969953 is an apocalyptic number.

It is an amenable number.

13511969953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13511969953 is an equidigital number, since it uses as much as digits as its factorization.

13511969953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 984150, while the sum is 52.

The spelling of 13511969953 in words is "thirteen billion, five hundred eleven million, nine hundred sixty-nine thousand, nine hundred fifty-three".