Base | Representation |
---|---|
bin | 1100010010100000111010… |
… | …1000101110000000011010 |
3 | 1202211202101100000002010102 |
4 | 3010220032220232000122 |
5 | 3232341002420342232 |
6 | 44423231431415402 |
7 | 2563140140424305 |
oct | 304501650560032 |
9 | 52752340002112 |
10 | 13512212668442 |
11 | 433a551874804 |
12 | 1622910824562 |
13 | 77027203c307 |
14 | 349dcd1c5b3c |
15 | 18673c548662 |
hex | c4a0ea2e01a |
13512212668442 has 4 divisors (see below), whose sum is σ = 20268319002666. Its totient is φ = 6756106334220.
The previous prime is 13512212668441. The next prime is 13512212668463. The reversal of 13512212668442 is 24486621221531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9940267646761 + 3571945021681 = 3152819^2 + 1889959^2 .
It is not an unprimeable number, because it can be changed into a prime (13512212668441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3378053167109 + ... + 3378053167112.
Almost surely, 213512212668442 is an apocalyptic number.
13512212668442 is a deficient number, since it is larger than the sum of its proper divisors (6756106334224).
13512212668442 is an equidigital number, since it uses as much as digits as its factorization.
13512212668442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6756106334223.
The product of its digits is 1105920, while the sum is 47.
Adding to 13512212668442 its reverse (24486621221531), we get a palindrome (37998833889973).
The spelling of 13512212668442 in words is "thirteen trillion, five hundred twelve billion, two hundred twelve million, six hundred sixty-eight thousand, four hundred forty-two".
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