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13513167053 = 59392275327
BaseRepresentation
bin11001001010111001…
…01001000011001101
31021212202102000022122
430211130221003031
5210133332321203
610112522022325
7655604011331
oct144534510315
937782360278
1013513167053
115804915461
1227516479a5
1313747b7049
1492298b7c1
1554151b538
hex3257290cd

13513167053 has 4 divisors (see below), whose sum is σ = 13515448320. Its totient is φ = 13510885788.

The previous prime is 13513167049. The next prime is 13513167079. The reversal of 13513167053 is 35076131531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13513167053 - 22 = 13513167049 is a prime.

It is a super-3 number, since 3×135131670533 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13513167953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1131725 + ... + 1143602.

It is an arithmetic number, because the mean of its divisors is an integer number (3378862080).

Almost surely, 213513167053 is an apocalyptic number.

It is an amenable number.

13513167053 is a deficient number, since it is larger than the sum of its proper divisors (2281267).

13513167053 is an equidigital number, since it uses as much as digits as its factorization.

13513167053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2281266.

The product of its (nonzero) digits is 28350, while the sum is 35.

Adding to 13513167053 its reverse (35076131531), we get a palindrome (48589298584).

The spelling of 13513167053 in words is "thirteen billion, five hundred thirteen million, one hundred sixty-seven thousand, fifty-three".

Divisors: 1 5939 2275327 13513167053