Base | Representation |
---|---|
bin | 11001001010111010… |
… | …10011100100010011 |
3 | 1021212202201212012122 |
4 | 30211131103210103 |
5 | 210133403404303 |
6 | 10112525444455 |
7 | 655605335135 |
oct | 144535234423 |
9 | 37782655178 |
10 | 13513341203 |
11 | 5804a2428a |
12 | 275171072b |
13 | 13748483ab |
14 | 9229d5055 |
15 | 541552e38 |
hex | 325753913 |
13513341203 has 2 divisors, whose sum is σ = 13513341204. Its totient is φ = 13513341202.
The previous prime is 13513341187. The next prime is 13513341211. The reversal of 13513341203 is 30214331531.
13513341203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13513341203 - 24 = 13513341187 is a prime.
It is a super-2 number, since 2×135133412032 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13513341103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756670601 + 6756670602.
It is an arithmetic number, because the mean of its divisors is an integer number (6756670602).
Almost surely, 213513341203 is an apocalyptic number.
13513341203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13513341203 is an equidigital number, since it uses as much as digits as its factorization.
13513341203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 13513341203 its reverse (30214331531), we get a palindrome (43727672734).
The spelling of 13513341203 in words is "thirteen billion, five hundred thirteen million, three hundred forty-one thousand, two hundred three".
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