Base | Representation |
---|---|
bin | 111110111011010011… |
… | …1010011100101101101 |
3 | 110220210201110112201011 |
4 | 1331312213103211231 |
5 | 4203223301022032 |
6 | 142025114345221 |
7 | 12522514026544 |
oct | 1756647234555 |
9 | 426721415634 |
10 | 135134001517 |
11 | 52345691499 |
12 | 2223412b211 |
13 | c987720358 |
14 | 677d28d15b |
15 | 37ad939247 |
hex | 1f769d396d |
135134001517 has 2 divisors, whose sum is σ = 135134001518. Its totient is φ = 135134001516.
The previous prime is 135134001467. The next prime is 135134001523. The reversal of 135134001517 is 715100431531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126034940196 + 9099061321 = 355014^2 + 95389^2 .
It is a cyclic number.
It is not a de Polignac number, because 135134001517 - 231 = 132986517869 is a prime.
It is a super-2 number, since 2×1351340015172 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135134001547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67567000758 + 67567000759.
It is an arithmetic number, because the mean of its divisors is an integer number (67567000759).
Almost surely, 2135134001517 is an apocalyptic number.
It is an amenable number.
135134001517 is a deficient number, since it is larger than the sum of its proper divisors (1).
135134001517 is an equidigital number, since it uses as much as digits as its factorization.
135134001517 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 31.
The spelling of 135134001517 in words is "one hundred thirty-five billion, one hundred thirty-four million, one thousand, five hundred seventeen".
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