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135134026541 = 679791987879
BaseRepresentation
bin111110111011010011…
…1011001101100101101
3110220210201111211000222
41331312213121230231
54203223302322131
6142025115101125
712522514162523
oct1756647315455
9426721454028
10135134026541
11523456a9278
12222341417a5
13c98772b867
14677d298313
1537ad94187b
hex1f769d9b2d

135134026541 has 4 divisors (see below), whose sum is σ = 135136082400. Its totient is φ = 135131970684.

The previous prime is 135134026537. The next prime is 135134026549. The reversal of 135134026541 is 145620431531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 145620431531 = 752319356697.

It is a cyclic number.

It is not a de Polignac number, because 135134026541 - 22 = 135134026537 is a prime.

It is a super-2 number, since 2×1351340265412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135134026549) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 925961 + ... + 1061918.

It is an arithmetic number, because the mean of its divisors is an integer number (33784020600).

Almost surely, 2135134026541 is an apocalyptic number.

It is an amenable number.

135134026541 is a deficient number, since it is larger than the sum of its proper divisors (2055859).

135134026541 is an equidigital number, since it uses as much as digits as its factorization.

135134026541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2055858.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 135134026541 in words is "one hundred thirty-five billion, one hundred thirty-four million, twenty-six thousand, five hundred forty-one".

Divisors: 1 67979 1987879 135134026541