Base | Representation |
---|---|
bin | 11001001010111011… |
… | …11010010101001111 |
3 | 1021212210000221000101 |
4 | 30211131322111033 |
5 | 210133423444413 |
6 | 10112533111531 |
7 | 655606566064 |
oct | 144535722517 |
9 | 37783027011 |
10 | 13513499983 |
11 | 5805022605 |
12 | 27517885a7 |
13 | 13748a2749 |
14 | 922a36c6b |
15 | 541584edd |
hex | 32577a54f |
13513499983 has 2 divisors, whose sum is σ = 13513499984. Its totient is φ = 13513499982.
The previous prime is 13513499957. The next prime is 13513500029. The reversal of 13513499983 is 38999431531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13513499983 - 213 = 13513491791 is a prime.
It is a super-2 number, since 2×135134999832 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13513499383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756749991 + 6756749992.
It is an arithmetic number, because the mean of its divisors is an integer number (6756749992).
Almost surely, 213513499983 is an apocalyptic number.
13513499983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13513499983 is an equidigital number, since it uses as much as digits as its factorization.
13513499983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3149280, while the sum is 55.
The spelling of 13513499983 in words is "thirteen billion, five hundred thirteen million, four hundred ninety-nine thousand, nine hundred eighty-three".
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