1351514041 has 4 divisors (see below), whose sum is σ = 1351589632. Its totient is φ = 1351438452.

The previous prime is 1351514033. The next prime is 1351514051. The reversal of 1351514041 is 1404151531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1404151531 = 167 ⋅8408093.

It is a cyclic number.

It is not a de Polignac number, because 1351514041 - 2³ = 1351514033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1351513997 and 1351514015.

It is not an unprimeable number, because it can be changed into a prime (1351514051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5740 + ... + 52306.

It is an arithmetic number, because the mean of its divisors is an integer number (337897408).

Almost surely, 2^1351514041 is an apocalyptic number.

It is an amenable number.

1351514041 is a deficient number, since it is larger than the sum of its proper divisors (75591).

1351514041 is an equidigital number, since it uses as much as digits as its factorization.

1351514041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75590.

The product of its (nonzero) digits is 1200, while the sum is 25.

The square root of 1351514041 is about 36762.9438565521. The cubic root of 1351514041 is about 1105.6224637293.

Adding to 1351514041 its reverse (1404151531), we get a palindrome (2755665572).

It can be divided in two parts, 13515 and 14041, that added together give a square (27556 = 166²).

The spelling of 1351514041 in words is "one billion, three hundred fifty-one million, five hundred fourteen thousand, forty-one".