Base | Representation |
---|---|
bin | 111110111011111010… |
… | …1000111101011111101 |
3 | 110220212010211220011102 |
4 | 1331313311013223331 |
5 | 4203244011244442 |
6 | 142031123502445 |
7 | 12523152305411 |
oct | 1756765075375 |
9 | 426763756142 |
10 | 135154399997 |
11 | 52356154141 |
12 | 2223ab27a25 |
13 | c98ba12c66 |
14 | 6781c7cd41 |
15 | 37b0618232 |
hex | 1f77d47afd |
135154399997 has 2 divisors, whose sum is σ = 135154399998. Its totient is φ = 135154399996.
The previous prime is 135154399969. The next prime is 135154400027. The reversal of 135154399997 is 799993451531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128637712921 + 6516687076 = 358661^2 + 80726^2 .
It is an emirp because it is prime and its reverse (799993451531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135154399997 - 216 = 135154334461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135154399967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67577199998 + 67577199999.
It is an arithmetic number, because the mean of its divisors is an integer number (67577199999).
Almost surely, 2135154399997 is an apocalyptic number.
It is an amenable number.
135154399997 is a deficient number, since it is larger than the sum of its proper divisors (1).
135154399997 is an equidigital number, since it uses as much as digits as its factorization.
135154399997 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41334300, while the sum is 65.
The spelling of 135154399997 in words is "one hundred thirty-five billion, one hundred fifty-four million, three hundred ninety-nine thousand, nine hundred ninety-seven".
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