Base | Representation |
---|---|
bin | 10011101010110011100… |
… | …111011000101000100001 |
3 | 11210012210122021121200112 |
4 | 103222303213120220201 |
5 | 134121121043131441 |
6 | 2512533125501105 |
7 | 166436505304433 |
oct | 23526347305041 |
9 | 4705718247615 |
10 | 1351633177121 |
11 | 4812517673a7 |
12 | 199b57271795 |
13 | 9a5c6318056 |
14 | 495c2b68653 |
15 | 2525bd6e4eb |
hex | 13ab39d8a21 |
1351633177121 has 2 divisors, whose sum is σ = 1351633177122. Its totient is φ = 1351633177120.
The previous prime is 1351633177067. The next prime is 1351633177123. The reversal of 1351633177121 is 1217713361531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 705707524096 + 645925653025 = 840064^2 + 803695^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351633177121 - 218 = 1351632914977 is a prime.
Together with 1351633177123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1351633177123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675816588560 + 675816588561.
It is an arithmetic number, because the mean of its divisors is an integer number (675816588561).
Almost surely, 21351633177121 is an apocalyptic number.
It is an amenable number.
1351633177121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351633177121 is an equidigital number, since it uses as much as digits as its factorization.
1351633177121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 79380, while the sum is 41.
The spelling of 1351633177121 in words is "one trillion, three hundred fifty-one billion, six hundred thirty-three million, one hundred seventy-seven thousand, one hundred twenty-one".
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