Base | Representation |
---|---|
bin | 10011101010110011101… |
… | …100111101000100101111 |
3 | 11210012210202000210101221 |
4 | 103222303230331010233 |
5 | 134121121431341403 |
6 | 2512533221044211 |
7 | 166436523565102 |
oct | 23526354750457 |
9 | 4705722023357 |
10 | 1351634637103 |
11 | 4812525742a3 |
12 | 199b57856667 |
13 | 9a5c670974a |
14 | 495c3028739 |
15 | 2525c05bdbd |
hex | 13ab3b3d12f |
1351634637103 has 2 divisors, whose sum is σ = 1351634637104. Its totient is φ = 1351634637102.
The previous prime is 1351634637097. The next prime is 1351634637107. The reversal of 1351634637103 is 3017364361531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1351634637103 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1351634637103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351634637107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675817318551 + 675817318552.
It is an arithmetic number, because the mean of its divisors is an integer number (675817318552).
Almost surely, 21351634637103 is an apocalyptic number.
1351634637103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351634637103 is an equidigital number, since it uses as much as digits as its factorization.
1351634637103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 43.
Adding to 1351634637103 its reverse (3017364361531), we get a palindrome (4368998998634).
The spelling of 1351634637103 in words is "one trillion, three hundred fifty-one billion, six hundred thirty-four million, six hundred thirty-seven thousand, one hundred three".
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