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1351714211414 = 2796551015101
BaseRepresentation
bin10011101010111000011…
…100100000011001010110
311210020000021202120211122
4103222320130200121112
5134121302314231124
62512545142403542
7166441511136140
oct23527034403126
94706007676748
101351714211414
11481293484696
12199b7a4305b2
139a60a04b138
14495cd81dc90
152526402975e
hex13ab8720656

1351714211414 has 8 divisors (see below), whose sum is σ = 2317224362448. Its totient is φ = 579306090600.

The previous prime is 1351714211401. The next prime is 1351714211431. The reversal of 1351714211414 is 4141124171531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48275507537 + ... + 48275507564.

It is an arithmetic number, because the mean of its divisors is an integer number (289653045306).

Almost surely, 21351714211414 is an apocalyptic number.

1351714211414 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1351714211414 is a deficient number, since it is larger than the sum of its proper divisors (965510151034).

1351714211414 is an equidigital number, since it uses as much as digits as its factorization.

1351714211414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96551015110.

The product of its digits is 13440, while the sum is 35.

Adding to 1351714211414 its reverse (4141124171531), we get a palindrome (5492838382945).

The spelling of 1351714211414 in words is "one trillion, three hundred fifty-one billion, seven hundred fourteen million, two hundred eleven thousand, four hundred fourteen".

Divisors: 1 2 7 14 96551015101 193102030202 675857105707 1351714211414