Base | Representation |
---|---|
bin | 1100010010111110110010… |
… | …0100101111011111101111 |
3 | 1202212112002011011101200021 |
4 | 3010233230210233133233 |
5 | 3233003413132311330 |
6 | 44431035231143011 |
7 | 2563542634316410 |
oct | 304575444573757 |
9 | 52775064141607 |
10 | 13520231135215 |
11 | 4342997005552 |
12 | 162438a074a67 |
13 | 770c4c3499cc |
14 | 34a5500d9807 |
15 | 186a5b49067a |
hex | c4bec92f7ef |
13520231135215 has 16 divisors (see below), whose sum is σ = 18545680802880. Its totient is φ = 9269190869760.
The previous prime is 13520231135189. The next prime is 13520231135231. The reversal of 13520231135215 is 51253113202531.
It is a de Polignac number, because none of the positive numbers 2k-13520231135215 is a prime.
It is a super-2 number, since 2×135202311352152 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37835580 + ... + 38191249.
It is an arithmetic number, because the mean of its divisors is an integer number (1159105050180).
Almost surely, 213520231135215 is an apocalyptic number.
13520231135215 is a deficient number, since it is larger than the sum of its proper divisors (5025449667665).
13520231135215 is an equidigital number, since it uses as much as digits as its factorization.
13520231135215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76031922.
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 13520231135215 its reverse (51253113202531), we get a palindrome (64773344337746).
The spelling of 13520231135215 in words is "thirteen trillion, five hundred twenty billion, two hundred thirty-one million, one hundred thirty-five thousand, two hundred fifteen".
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