13520333254147 has 2 divisors, whose sum is σ = 13520333254148. Its totient is φ = 13520333254146.

The previous prime is 13520333254081. The next prime is 13520333254199. The reversal of 13520333254147 is 74145233302531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13520333254147 - 2¹¹ = 13520333252099 is a prime.

It is a super-2 number, since 2×13520333254147² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13520333254847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760166627073 + 6760166627074.

It is an arithmetic number, because the mean of its divisors is an integer number (6760166627074).

Almost surely, 2^{13520333254147} is an apocalyptic number.

13520333254147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13520333254147 is an equidigital number, since it uses as much as digits as its factorization.

13520333254147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 907200, while the sum is 43.

Adding to 13520333254147 its reverse (74145233302531), we get a palindrome (87665566556678).

The spelling of 13520333254147 in words is "thirteen trillion, five hundred twenty billion, three hundred thirty-three million, two hundred fifty-four thousand, one hundred forty-seven".