13520333254081 has 2 divisors, whose sum is σ = 13520333254082. Its totient is φ = 13520333254080.

The previous prime is 13520333254063. The next prime is 13520333254147. The reversal of 13520333254081 is 18045233302531.

It is a happy number.

13520333254081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7624275141681 + 5896058112400 = 2761209^2 + 2428180^2 .

It is a cyclic number.

It is not a de Polignac number, because 13520333254081 - 2⁹ = 13520333253569 is a prime.

It is a super-2 number, since 2×13520333254081² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13520333254481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760166627040 + 6760166627041.

It is an arithmetic number, because the mean of its divisors is an integer number (6760166627041).

Almost surely, 2^{13520333254081} is an apocalyptic number.

It is an amenable number.

13520333254081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13520333254081 is an equidigital number, since it uses as much as digits as its factorization.

13520333254081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 13520333254081 in words is "thirteen trillion, five hundred twenty billion, three hundred thirty-three million, two hundred fifty-four thousand, eighty-one".