Base | Representation |
---|---|
bin | 1100010010111111011111… |
… | …0110110111010011000111 |
3 | 1202212112120100100211100201 |
4 | 3010233313312313103013 |
5 | 3233004310112411033 |
6 | 44431110112351331 |
7 | 2563550423330266 |
oct | 304576766672307 |
9 | 52775510324321 |
10 | 13520420435143 |
11 | 4342a8394a376 |
12 | 1624421545547 |
13 | 770c7c6288bb |
14 | 34a56b2d45dd |
15 | 186a6cdd447d |
hex | c4bf7db74c7 |
13520420435143 has 8 divisors (see below), whose sum is σ = 13716287728416. Its totient is φ = 13324704220800.
The previous prime is 13520420435131. The next prime is 13520420435147. The reversal of 13520420435143 is 34153402402531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13520420435143 - 221 = 13520418337991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13520420435147) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37589446 + ... + 37947427.
It is an arithmetic number, because the mean of its divisors is an integer number (1714535966052).
Almost surely, 213520420435143 is an apocalyptic number.
13520420435143 is a deficient number, since it is larger than the sum of its proper divisors (195867293273).
13520420435143 is an equidigital number, since it uses as much as digits as its factorization.
13520420435143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75539465.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 13520420435143 its reverse (34153402402531), we get a palindrome (47673822837674).
The spelling of 13520420435143 in words is "thirteen trillion, five hundred twenty billion, four hundred twenty million, four hundred thirty-five thousand, one hundred forty-three".
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