Base | Representation |
---|---|
bin | 11001001011110001… |
… | …01000010011001101 |
3 | 1021220021012202201220 |
4 | 30211320220103031 |
5 | 210142222112023 |
6 | 10113343153553 |
7 | 656023250022 |
oct | 144570502315 |
9 | 37807182656 |
10 | 13520504013 |
11 | 5808a76865 |
12 | 2753ba58b9 |
13 | 1376185743 |
14 | 92393b549 |
15 | 541eba3e3 |
hex | 325e284cd |
13520504013 has 4 divisors (see below), whose sum is σ = 18027338688. Its totient is φ = 9013669340.
The previous prime is 13520504009. The next prime is 13520504017. The reversal of 13520504013 is 31040502531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (13520504009) and next prime (13520504017).
It is a cyclic number.
It is not a de Polignac number, because 13520504013 - 22 = 13520504009 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13520504017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2253417333 + ... + 2253417338.
It is an arithmetic number, because the mean of its divisors is an integer number (4506834672).
Almost surely, 213520504013 is an apocalyptic number.
It is an amenable number.
13520504013 is a deficient number, since it is larger than the sum of its proper divisors (4506834675).
13520504013 is an equidigital number, since it uses as much as digits as its factorization.
13520504013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4506834674.
The product of its (nonzero) digits is 1800, while the sum is 24.
The spelling of 13520504013 in words is "thirteen billion, five hundred twenty million, five hundred four thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •