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135214400043202 = 267607200021601
BaseRepresentation
bin11110101111101000001110…
…010010000111100011000010
3122201202101000000122002100211
4132233220032102013203002
5120210323042402340302
61155324345435304334
740323626611601104
oct3657501622074302
9581671000562324
10135214400043202
113a0a1117879537
12131b9558bab0aa
135a5a88110262c
1425565aa2b5574
151097384543ad7
hex7afa0e4878c2

135214400043202 has 4 divisors (see below), whose sum is σ = 202821600064806. Its totient is φ = 67607200021600.

The previous prime is 135214400043197. The next prime is 135214400043253. The reversal of 135214400043202 is 202340004412531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 82526850256041 + 52687549787161 = 9084429^2 + 7258619^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33803600010799 + ... + 33803600010802.

Almost surely, 2135214400043202 is an apocalyptic number.

135214400043202 is a deficient number, since it is larger than the sum of its proper divisors (67607200021604).

135214400043202 is an equidigital number, since it uses as much as digits as its factorization.

135214400043202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67607200021603.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 135214400043202 its reverse (202340004412531), we get a palindrome (337554404455733).

The spelling of 135214400043202 in words is "one hundred thirty-five trillion, two hundred fourteen billion, four hundred million, forty-three thousand, two hundred two".

Divisors: 1 2 67607200021601 135214400043202