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13521524953 is a prime number
BaseRepresentation
bin11001001011111001…
…00001100011011001
31021220100010122012111
430211330201203121
5210143002244303
610113421112321
7656035031356
oct144574414331
937810118174
1013521524953
115809603912
1227543b86a1
131376452351
14923b2562d
1554211cb6d
hex325f218d9

13521524953 has 2 divisors, whose sum is σ = 13521524954. Its totient is φ = 13521524952.

The previous prime is 13521524927. The next prime is 13521525041. The reversal of 13521524953 is 35942512531.

13521524953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10841599129 + 2679925824 = 104123^2 + 51768^2 .

It is a cyclic number.

It is not a de Polignac number, because 13521524953 - 217 = 13521393881 is a prime.

It is not a weakly prime, because it can be changed into another prime (13521524053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760762476 + 6760762477.

It is an arithmetic number, because the mean of its divisors is an integer number (6760762477).

Almost surely, 213521524953 is an apocalyptic number.

It is an amenable number.

13521524953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13521524953 is an equidigital number, since it uses as much as digits as its factorization.

13521524953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 162000, while the sum is 40.

The spelling of 13521524953 in words is "thirteen billion, five hundred twenty-one million, five hundred twenty-four thousand, nine hundred fifty-three".