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135215433101 = 719316490443
BaseRepresentation
bin111110111101101110…
…1111100010110001101
3110221000101200200211202
41331323131330112031
54203410122324401
6142041143555245
712524523134450
oct1757335742615
9427011620752
10135215433101
1152387650221
122225745bb25
13c99b562218
14678a009497
1537b5b7206b
hex1f7b77c58d

135215433101 has 4 divisors (see below), whose sum is σ = 154531923552. Its totient is φ = 115898942652.

The previous prime is 135215433077. The next prime is 135215433103. The reversal of 135215433101 is 101334512531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 101334512531 = 714476358933.

It is a cyclic number.

It is not a de Polignac number, because 135215433101 - 26 = 135215433037 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135215433103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9658245215 + ... + 9658245228.

It is an arithmetic number, because the mean of its divisors is an integer number (38632980888).

Almost surely, 2135215433101 is an apocalyptic number.

It is an amenable number.

135215433101 is a deficient number, since it is larger than the sum of its proper divisors (19316490451).

135215433101 is an equidigital number, since it uses as much as digits as its factorization.

135215433101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19316490450.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 135215433101 its reverse (101334512531), we get a palindrome (236549945632).

The spelling of 135215433101 in words is "one hundred thirty-five billion, two hundred fifteen million, four hundred thirty-three thousand, one hundred one".

Divisors: 1 7 19316490443 135215433101