Base | Representation |
---|---|
bin | 11110101111110111010111… |
… | …111000110010111101000011 |
3 | 122201210220222201100121010001 |
4 | 132233313113320302331003 |
5 | 120211104401312223041 |
6 | 1155340035543220431 |
7 | 40325044000205503 |
oct | 3657672770627503 |
9 | 581726881317101 |
10 | 135230667304771 |
11 | 3a0a8005267965 |
12 | 13200738a47717 |
13 | 5a5c2743630ac |
14 | 25572b0937a03 |
15 | 10979d772d131 |
hex | 7afdd7e32f43 |
135230667304771 has 2 divisors, whose sum is σ = 135230667304772. Its totient is φ = 135230667304770.
The previous prime is 135230667304729. The next prime is 135230667304781. The reversal of 135230667304771 is 177403766032531.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (177403766032531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135230667304771 - 215 = 135230667272003 is a prime.
It is not a weakly prime, because it can be changed into another prime (135230667304721) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67615333652385 + 67615333652386.
It is an arithmetic number, because the mean of its divisors is an integer number (67615333652386).
Almost surely, 2135230667304771 is an apocalyptic number.
135230667304771 is a deficient number, since it is larger than the sum of its proper divisors (1).
135230667304771 is an equidigital number, since it uses as much as digits as its factorization.
135230667304771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13335840, while the sum is 55.
The spelling of 135230667304771 in words is "one hundred thirty-five trillion, two hundred thirty billion, six hundred sixty-seven million, three hundred four thousand, seven hundred seventy-one".
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