Base | Representation |
---|---|
bin | 11001001100000111… |
… | …10011111000000011 |
3 | 1021220110201200022101 |
4 | 30212003303320003 |
5 | 210143444410021 |
6 | 10113530051231 |
7 | 656060205142 |
oct | 144603637003 |
9 | 37813650271 |
10 | 13523435011 |
11 | 580a698979 |
12 | 2754b79b17 |
13 | 1376970868 |
14 | 9240a1759 |
15 | 542398a91 |
hex | 3260f3e03 |
13523435011 has 2 divisors, whose sum is σ = 13523435012. Its totient is φ = 13523435010.
The previous prime is 13523434997. The next prime is 13523435047. The reversal of 13523435011 is 11053432531.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13523435011 - 25 = 13523434979 is a prime.
It is not a weakly prime, because it can be changed into another prime (13523435911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6761717505 + 6761717506.
It is an arithmetic number, because the mean of its divisors is an integer number (6761717506).
Almost surely, 213523435011 is an apocalyptic number.
13523435011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13523435011 is an equidigital number, since it uses as much as digits as its factorization.
13523435011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 13523435011 its reverse (11053432531), we get a palindrome (24576867542).
The spelling of 13523435011 in words is "thirteen billion, five hundred twenty-three million, four hundred thirty-five thousand, eleven".
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