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13524400213 is a prime number
BaseRepresentation
bin11001001100001110…
…11111100001010101
31021220112112201022121
430212013133201111
5210144221301323
610114002455541
7656101335142
oct144607374125
937815481277
1013524400213
115810198065
1227553645b1
131376c1ac9c
149242733c9
155424d9a5d
hex3261df855

13524400213 has 2 divisors, whose sum is σ = 13524400214. Its totient is φ = 13524400212.

The previous prime is 13524400199. The next prime is 13524400231. The reversal of 13524400213 is 31200442531.

Together with next prime (13524400231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7827471729 + 5696928484 = 88473^2 + 75478^2 .

It is a cyclic number.

It is not a de Polignac number, because 13524400213 - 221 = 13522303061 is a prime.

It is a super-2 number, since 2×135244002132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13524400283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762200106 + 6762200107.

It is an arithmetic number, because the mean of its divisors is an integer number (6762200107).

Almost surely, 213524400213 is an apocalyptic number.

It is an amenable number.

13524400213 is a deficient number, since it is larger than the sum of its proper divisors (1).

13524400213 is an equidigital number, since it uses as much as digits as its factorization.

13524400213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13524400213 its reverse (31200442531), we get a palindrome (44724842744).

The spelling of 13524400213 in words is "thirteen billion, five hundred twenty-four million, four hundred thousand, two hundred thirteen".