Base | Representation |
---|---|
bin | 1100010011010010100010… |
… | …1011010000101010101111 |
3 | 1202220000202202021101221211 |
4 | 3010310220223100222233 |
5 | 3233100243304203312 |
6 | 44433313355335251 |
7 | 2564121231564562 |
oct | 304645053205257 |
9 | 52800682241854 |
10 | 13525534444207 |
11 | 4345168647045 |
12 | 162540a151527 |
13 | 7715b5c94576 |
14 | 34a8d45924d9 |
15 | 186c6bd5b3a7 |
hex | c4d28ad0aaf |
13525534444207 has 4 divisors (see below), whose sum is σ = 13727408092696. Its totient is φ = 13323660795720.
The previous prime is 13525534444193. The next prime is 13525534444217. The reversal of 13525534444207 is 70244443552531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13525534444207 - 227 = 13525400226479 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13525534444217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100936824144 + ... + 100936824277.
It is an arithmetic number, because the mean of its divisors is an integer number (3431852023174).
Almost surely, 213525534444207 is an apocalyptic number.
13525534444207 is a deficient number, since it is larger than the sum of its proper divisors (201873648489).
13525534444207 is an equidigital number, since it uses as much as digits as its factorization.
13525534444207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201873648488.
The product of its (nonzero) digits is 8064000, while the sum is 49.
Adding to 13525534444207 its reverse (70244443552531), we get a palindrome (83769977996738).
The spelling of 13525534444207 in words is "thirteen trillion, five hundred twenty-five billion, five hundred thirty-four million, four hundred forty-four thousand, two hundred seven".
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