Base | Representation |
---|---|
bin | 10011101011101110000… |
… | …001001101011101110010 |
3 | 11210022022221001002011210 |
4 | 103223232001031131302 |
5 | 134130122413310100 |
6 | 2513214251220550 |
7 | 166503004005615 |
oct | 23535601153562 |
9 | 4708287032153 |
10 | 1352613025650 |
11 | 481704877077 |
12 | 19a18b447756 |
13 | 9a72131ab93 |
14 | 49676d4c17c |
15 | 252b7dbec50 |
hex | 13aee04d772 |
1352613025650 has 96 divisors (see below), whose sum is σ = 3374253676800. Its totient is φ = 358571886400.
The previous prime is 1352613025633. The next prime is 1352613025681. The reversal of 1352613025650 is 565203162531.
It is a junction number, because it is equal to n+sod(n) for n = 1352613025599 and 1352613025608.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 125947981 + ... + 125958719.
It is an arithmetic number, because the mean of its divisors is an integer number (35148475800).
Almost surely, 21352613025650 is an apocalyptic number.
1352613025650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1352613025650, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1687126838400).
1352613025650 is an abundant number, since it is smaller than the sum of its proper divisors (2021640651150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1352613025650 is a wasteful number, since it uses less digits than its factorization.
1352613025650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15624 (or 15619 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 39.
The spelling of 1352613025650 in words is "one trillion, three hundred fifty-two billion, six hundred thirteen million, twenty-five thousand, six hundred fifty".
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