Base | Representation |
---|---|
bin | 11001001100111010… |
… | …00000011101001101 |
3 | 1021220221011020211211 |
4 | 30212131000131031 |
5 | 210202142241031 |
6 | 10114323414421 |
7 | 656200305112 |
oct | 144635003515 |
9 | 37827136754 |
10 | 13530040141 |
11 | 581339a462 |
12 | 2757224411 |
13 | 1378144117 |
14 | 924d00909 |
15 | 542c50bb1 |
hex | 32674074d |
13530040141 has 4 divisors (see below), whose sum is σ = 13530410784. Its totient is φ = 13529669500.
The previous prime is 13530040109. The next prime is 13530040159. The reversal of 13530040141 is 14104003531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14104003531 = 1361 ⋅10362971.
It is a cyclic number.
It is not a de Polignac number, because 13530040141 - 25 = 13530040109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13530040841) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123745 + ... + 205846.
It is an arithmetic number, because the mean of its divisors is an integer number (3382602696).
Almost surely, 213530040141 is an apocalyptic number.
It is an amenable number.
13530040141 is a deficient number, since it is larger than the sum of its proper divisors (370643).
13530040141 is an equidigital number, since it uses as much as digits as its factorization.
13530040141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 370642.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 13530040141 its reverse (14104003531), we get a palindrome (27634043672).
The spelling of 13530040141 in words is "thirteen billion, five hundred thirty million, forty thousand, one hundred forty-one".
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